Answer:
Specific heat capacity, = 2.1J/g°C
Explanation:
Given the following data;
Mass = 250g
Quantity of heat = 34.125kJ = 34.125 * 1000 = 34125 Joules.
Change in temperature = 65.0∘C
To find the specific heat capacity;
Heat capacity is given by the formula;
[tex] Q = mcdt[/tex]
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
Making c the subject of formula, we have;
[tex] c = \frac {Q}{mdt} [/tex]
Substituting into the equation, we have;
[tex] c = \frac {34125}{250*65} [/tex]
[tex] c = \frac {34125}{16250} [/tex]
Specific heat capacity, = 2.1J/g°C
