Answer:
Efficiency (%) = 20%
Explanation:
The question requires the determination of efficiency based on the given proportions in the diagram
The total energy supplied in the system = 10 J
The area representing the total energy supplied ≈ 90 unit²
The area representing the energy wasted ≈ 8 unit × 9 unit = 72 unit²
The area representing the useful energy ≈ 2 unit × 9 unit = 18 unit²
∴ 90 unit² = 10 J
1 unit² = 1/9 J
∴ The energy wasted ≈ 72 unit² × 1/9 J/unit² = 8 J
The useful energy ≈ 18 unit² × 1/9 J/unit² = 2 J
[tex]Efficiency \ (\%)= \dfrac{Useful \ Energy}{Energy \ Supplied} \times 100[/tex]
[tex]\therefore Efficiency \ (\%)= \dfrac{2 \ J}{10 \ J} \times 100= 20 \%[/tex]
