HELP PLEASE ! Write an equation of a line that passes through the point (4, 3) and is perpendicular to the graph of the equation y= -1/3x+4

HELP PLEASE Write an equation of a line that passes through the point 4 3 and is perpendicular to the graph of the equation y 13x4 class=

Respuesta :

Answer:

y = 3x - 9

Step-by-step explanation:

✔️Find the slope of the line perpendicular to the given graph of equation:

A line that is perpendicular to the graph of the equation y = -⅓x + 4, will have a slope value that is the negative reciprocal of the slope of the graph of the given equation.

The slope of y = -⅓x + 4 is -⅓.

Negative reciprocal of -⅓ = 3

Slope of the line (m) = 3

✔️Find the y-intercept (b):

Substitute (x, y) = (4, 3) and m = 3 into y = mx + b

3 = 3(4) + b

3 = 12 + b

3 - 12 = b

-9 = b

b = -9

✔️Write the equation:

Substitute m = 3 and b = -9 into y = mx + b

y = 3x + (-9)

y = 3x - 9