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Question 1 of 10
Suppose a normal distribution has a mean of 266 and a standard deviation of
12. What is P(x> 242)?
O A. 0.16
B. 0.475
C. 0.84
D. 0.975

Question 1 of 10 Suppose a normal distribution has a mean of 266 and a standard deviation of 12 What is Pxgt 242 O A 016 B 0475 C 084 D 0975 class=

Respuesta :

0.975 is P(x ≥242) with a mean of 266 and standard deviation of 12

Ver imagen craftyclub4u

The required value of P(x> 242) = is 0.975 for normal distribution. Option D is correct.

The normal distribution has a mean of 266 and a standard deviation of

12. What is P(x> 242) is to determine.

Whata  is normal distribution?

Normal distributions can be altered to standard normal distributions by the formula:

Z = (X - μ)/σ

Where x is a value from the initial normal distribution, μ is the mean of the initial normal distribution, and σ is the standard deviation of the initial normal distribution. The standard normal distribution is periodically called the z distribution.

Now,
z = X - 266 /12
p(x > 242) = P [(X - 266)/12 ≥ (242 - 266)/12]
p(x > 242) = P [z ≥ -24/12]
p(x > 242) = P [z ≥ -2]
p(x > 242) = P [z ≤ 2]
p(x > 242) = 0.975  (from Z table).


Thus, the required value of P(x> 242) = is 0.975. Option D is correct.


Learn more about normal distribution here:
https://brainly.com/question/12421652

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