Answer:
8.97 g H₂O
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
- Using Dimensional Analysis
Explanation:
Step 1: Define
3.00 × 10²³ particles H₂O
Step 2: Identify Conversions
Avogadro's Number
[Given] Molar Mass of H₂O - 18.0 g/mol
Step 3: Convert
- Set up: [tex]\displaystyle 3.00 \cdot 10^{23} \ particles \ H_2O(\frac{1 \ mol \ H_2O}{6.022 \cdot 10^{23} \ particles \ H_2O})(\frac{18.0 \ g \ H_2O}{1 \ mol \ H_2O})[/tex]
- Multiply/Divide: [tex]\displaystyle 8.96712 \ g \ H_2O[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
8.96712 g H₂O ≈ 8.97 g H₂O
