Answer:
1.83 × 10⁻⁷ mol Au
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
Step 1: Define
3.60 × 10⁻⁵ g Au (Gold)
Step 2: Identify Conversions
Molar Mass of Au - 196.97 g/mol
Step 3: Convert
- Set up: [tex]\displaystyle 3.60 \cdot 10^{-5} \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})[/tex]
- Multiply: [tex]\displaystyle 1.82769 \cdot 10^{-7} \ mol \ Au[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
1.82769 × 10⁻⁷ mol Au ≈ 1.83 × 10⁻⁷ mol Au
