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If both the pressure and volume of a given sample of an ideal gas are doubled, what happens to the temperature of the gas in Kelvins

Respuesta :

Answer: Four times

Explanation:

Given

If Pressure and Volume is double

For ideal gas

PV=nRT

where P=Pressure

V=volume

n=no of moles

R=gas constant

T=temperature

Initially

PV=nRT......(i)

after doubling

(2P)(2V)=nRT'.......(ii)

divide (i) and (ii)

[tex]\frac{PV}{4PV}=\frac{nRT}{nRT'}\\T'=4T[/tex]

So, Temperature becomes 4 times