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13-01-2021
Chemistry

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In the laboratory you are asked to make a 0.175 m barium sulfide solution using 15.4 grams of barium sulfide. How much water should you add

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17-01-2021

Answer:

0.5195 liters of water

Explanation:

First we convert 15.4 grams of barium sulfide (BaS) into moles, using its molar mass:

15.4 g ÷ 169.39 g/mol = 0.0909 mol

Then we calculate the required volume of water, using the definition of molarity:

molarity = moles / volume

0.175 M = 0.0909 mol / Volume

Volume = 0.5195 L

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