Answer:
Look below.
Step-by-step explanation:
[tex]2 (cotx)^{2} + 2 = 7 + 3 cot x\\let \\ u=cotx\\2u^2+2=7+3u\\2u^2-3u-5=0\\[/tex][tex]x=\frac{-(-3)+\sqrt{9-4(2)(-5))} }{2(2)} \\x=\frac{-(-3)-\sqrt{9-4(2)(-5))} }{2(2)} \\x={11/4}\\x=-1\\\\u=cotx\\x=arccotu\\x_{1}=arccot(-1) \\x_{2}=arccot(11/4)\\[/tex]
Calculate x1 and x2 in calculator. Check for domain.
