How do I do this problem (similar right triangles) please explain how you did it!!
ASAP!!!
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Answer:
by phythagoras theorem
(c+b)^2=(8)^2+(6)^2
(b+c)^2=64+36
(b+c)^2=100
b+c=√100
b+c=10.
by phythagoras theorem
(8)^2=(a)^2+(b)^2
64-b^2=a^2. {1}
by phythagoras theorem
(6)^2=(a)^2+(c)^2
36-c^2=a^2. {2}
In equation 1 and 2,
64-b^2=36-c^2
64-36= -c^2+b^2
28= b^2-c^2
28=(b+c)(b-c)
28=10(b-c)
b-c=28/10
b-c=2.8.
b+c=10
b-c=2.8
subtract both equations
c=3.6
option A is correct.