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A solution is made by mixing 100.g of acetic acid HCH3CO2 and 48.g of acetone CH32CO. Calculate the mole fraction of acetic acid in this solution. Round your answer to 3 significant digits.

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Answer:

[tex]x_{A.A}=0.668[/tex]

Explanation:

Hello!

In this case, since the mole fraction involves the moles of each substance, we first compute them considering the molar masses of acetic acid and acetone to be 60.052 and 58.08 g/mol respectively:

[tex]n_{A.A}=\frac{100gA.A}{60.052g/mol}=1.67molA.A\\n_{acetone}=\frac{48gAcetone}{58.08g/mol} =0.824molAcetone[/tex]

Thus, the mole fraction of acetic acid is computed below:

[tex]x_{A.A}=\frac{n_{A.A}}{n_{A.A}+n_{Acetone}} =\frac{1.67mol}{1.67mol+0.826mol}\\\\ x_{A.A}=0.668[/tex]

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