Answer:
The range of the ball is 11.6 meters
Explanation:
Projectile Motion
It's the type of motion that experiences an object launched with an initial angle and moves along a curved path exclusively under the action of gravity.
Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:
[tex]\displaystyle d={\frac {v_o^{2}\sin(2\theta )}{g}}[/tex]
The football is kicked with an initial speed of vo=11 m/s at an angle of θ=35°.
Calculating the range:
[tex]\displaystyle d={\frac {11^{2}\sin(2\cdot 35^\circ)}{9.8}}[/tex]
[tex]\displaystyle d={\frac {121\sin(70^\circ)}{9.8}}[/tex]
d = 11.6 m
The range of the ball is 11.6 meters
