Answer:
Net charge inside the cube is 321.6 C
Explanation:
Given charge density function is ρ = [tex]xy^2 e^{2z}[/tex]
side of cube is 2m
According to the definition of volume charge density total charge is given by
q = total charge = [tex]\int {\rho} \, dv[/tex] where dv = dxdydz is the volume element
on substututing the respected values we get
q = [tex]\int\limits^2_0 {x} \, dx \int\limits^2_0 {y^2} \, dy \int\limits^2_0 {e^2^z} \, dz[/tex]
on solving the above integration we get
q = [tex]\frac{x^2}{2}[/tex] x [tex]\frac{y^3}{3}[/tex] x [tex]\frac{e^2^z}{2}[/tex]
⇒ q = 321.6 C
Therefore net charge inside the cube is 321.6 C
