Answer:
The submarine is 10.4 km far from its base.
Step-by-step explanation:
Given that:
Distance traveled east = 7km
Distance traveled north = 12.5 km
This is will form a right triangle, where the distance from east to north is hypotenuse.
Here,
a = 7 , b = x and c = 12.5
Using Pythagorean theorem,
[tex]a^2+b^2=c^2\\(7)^2+x^2=(12.5)^2\\49+x^2=156.25\\x^2=156.25-49\\x^2=107.25[/tex]
Taking square root on both sides
[tex]\sqrt{x^2}=\sqrt{107.25}\\x=10.4[/tex]
Hence,
The submarine is 10.4 km far from its base.
