Answer:
21 m/s
Explanation:
If
m1 = mass of 1875 kg car
u1 initial speed of 187 kg car = 23.0 m/s
m2 = mass of 1025 kg car
u2= initial speed of 1025 kg car = 17.0 m/s
Since they stuck together, they have a common final velocity v
From principle of conservation of linear momentum
m1u1 + m2u2 = (m1 + m2) v
v= m1u1 + m2u2/(m1 + m2)
v= 1875 × 23 + 1025× 17/(1875 + 1025)
v= 43125 + 17425/2900
v= 21 m/s
The final velocity of both cars is 20.87 m/s.
Given that the two cars have a mass of 1875 kg and 1025 kg respectively and the velocity of both the cars is 23.0 m/s and 17.0 m/s.
The common velocity of both cars is given below.
[tex]v (m_1+ m_2) = m_1u_1 + m_2u_2[/tex]
Where v is the final velocity of both cars, m1 and m2 are the mass of both cars respectively. u1 and u2 are the initial velocities of both cars.
Substituting the values, we get the final velocity.
[tex]v ( 1875 + 1025) = 1875 \times 23 + 1025 \times 17[/tex]
[tex]v = 20.87 \;\rm m/s[/tex]
Hence we can conclude that the final velocity of both the cars is 20.87 m/s.
To know more about the velocity, follow the link given below.
https://brainly.com/question/862972.
