what is the area of the unshaded region of the rectangle? part 1. Show work please
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Answer:
96 m²
Step-by-step explanation:
The unshaded region is a right triangle.
The area (A) of the triangle is calculated as
A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the perpendicular height )
Calculate b using Pythagoras' identity in the right triangle
b² + 16² = 20²
b² + 256 = 400 ( subtract 256 from both sides )
b² = 144 ( take the square root of both sides )
b = [tex]\sqrt{144}[/tex] = 12
Thus area of unshaded region is
A = [tex]\frac{1}{2}[/tex] × 12 × 16 = 6 × 16 = 96 m²
Answer:
[tex]\displaystyle 96\:m^2[/tex]
Step-by-step explanation:
You can easily solve this using Pythagorean Triplets:
[tex]\displaystyle 3, 4, 5 \\ 6, 8, 10 \\ 9, 12, 15 \\ \boxed{12, 16, 20}[/tex]
The shorter leg is twelve metres long. Now you must find the area of this right triangle:
[tex]\displaystyle \frac{hb}{2} = A\:OR\:\frac{1}{2}hb = A \\ \\ \frac{[16][12]}{2} = \frac{192}{2} = 96\:OR\:\frac{1}{2}[16][12] = \frac{1}{2}[192] = 96[/tex]
You see how swift that was?
I am joyous to assist you at any time.