The percentage by mass of ammonium fluoride in the solution : 6.738%
Given
18.7 g of NH4F solution
1.26 g NH4F
Required
The percentage by mass
Solution
[tex]\tt \%mass=\dfrac{mass~solute}{mass~solution}\times 100\%[/tex]
mass solute = mass Ammonium fluoride
mass solute = 1.26 g
mass solution = 18.7 g
Input the value :
[tex]\tt \%mass=\dfrac{1.26}{18.7}\times 100\%\\\\\%mass=6.738[/tex]