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In a class, there are 18 girls and 14 boys. If the teacher selects two students at random to attend a party with the principal, what is the probability that the two students are the same sex?

Respuesta :

Answer:

0.492 is the answer

Step-by-step explanation:

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The probability that the two students are the same sex is 0.49.

Since the class contain 32 (18+14) children out of which  18 girls and 14 boys.

First step

Using general multiplication rule

P(Two girls)=P(First girls)×P(Second girl; First girl)

P(Two girls)=18/32×17/31

P(Two girls)=18×17/32×31

P(Two girls)=306/992

P(Two boys)=P(First boys)×P(Second boys; First boys)

P(Two girls)=14/32×13/31

P(Two girls)=14×13/32×31

P(Two girls)=182/992

Second step

Use addition rule for mutually exclusive events

P(Same sex)=P(Two girls)×P(Two boys)

P(Same sex)=306/992×182/992

P(Same sex)=306+182/992

P(Same sex)=488/992

P(Same sex)=61/124

P(Same sex)=0.49

Inconclusion the probability that the two students are the same sex is 0.49.

Learn more here:

https://brainly.com/question/24156895

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