Can someone please help me and explain if you can
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Answer:
∠6=116°
Step-by-step explanation:
Buckle up :)
[tex]-2x+94=-5x+139[/tex]
Solve for x. Subtract 94 from both sides:
[tex]-2x+94-94=-5x+139-94\\\\-2x=-5x+45[/tex]
Add 5x to both sides:
[tex]-2x+5x=-5x+5x+45\\\\3x=45[/tex]
Divide both sides by 3:
[tex]\frac{3x}{3} =\frac{45}{3} \\\\x=15[/tex]
Insert the value of x into angle 4 because they are same-side interior angles. This is because they are on the same side of the transversal and within the parallel lines. Same-side interior angles are supplementary, so their value will add up to 180°. Therefore, in order to find angle 6, we need to first find the true value of angle 4:
[tex]x=15\\\\-2(15)+94\\\\-30+94\\\\64[/tex]
∠4 is 64°. Use ∠a+∠b=180 to find angle 6:
[tex]a+64=180[/tex]
a represents angle 6. Subtract 64 from both sides:
[tex]a+64-64=180-64\\\\a=116[/tex]
Angle 6 has a measure of 116°.
:Done