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Review the graph of complex number z.

On a coordinate plane, the y-axis is labeled imaginary and the x-axis is labeled real. Point z is at (negative 6, 6).

What is the polar form of z?

6 StartRoot 2 EndRoot(cos(135°) + isin(135°))
6 StartRoot 3 EndRoot(cos(135°) + isin(135°))
6 StartRoot 2 EndRoot(cos(225°) + isin(225°))
6 StartRoot 3 EndRoot(cos(225°) + isin(225°))

Review the graph of complex number z On a coordinate plane the yaxis is labeled imaginary and the xaxis is labeled real Point z is at negative 6 6 What is the p class=

Respuesta :

sqdancefan

9514 1404 393

Answer:

  [tex]6\sqrt{2} (\cos(135^{\circ})+i\sin(135^{\circ}))[/tex]

Step-by-step explanation:

The angle to the point in the second quadrant is measured from the positive real axis (the x-axis). Second quadrant angles are between 90° and 180°, leaving the 135° choices as the only ones that make sense.

The magnitude of z is the root of the sum of the squares of its components:

  |z| = √((-6)^2 +6^2) = 6√2

So, the polar form of z is ...

  [tex]\boxed{6\sqrt{2} (\cos(135^{\circ})+i\sin(135^{\circ}))}[/tex]

this matches the first choice

rojasjacob15

Answer:

Its a ^_^

Step-by-step explanation:

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