The required logarithm form is -2log5
Given the exponential form of an equation expressed as;
[tex](5)^{-2} = 1/25[/tex]
For us to change the exponential form into logarithmic equation, first we need to identify the base, move it to the other side of the expression and then take the logarithm
Take the logarithm of both sides
[tex]= log(5)^{-2} \\=-2log5\\[/tex]
Hence the required logarithm form is -2log5
Learn more on logarithm here: https://brainly.com/question/17622052