A boat uses its motor to increase its speed from 5 m/s to 7 m/s. If the boat has a mass of
250 kg, what was the impulse applied by the motor?

Respuesta :

Answer:

J = 500 kg-m/s

Explanation:

Given that,

Initial speed of the motor, u = 5 m/s

Final speed of the motor, v = 7 m/s

Mass of the boat, m = 250 kg

We need to find the impulse applied by the motor. We know that impulse is equal to the change in momentum. It is represented by letter J.

J = m(v-u)

J = 250 (7-5)

J = 500 kg-m/s

Hence, the impulse applied by the motor is 500 kg-m/s.