1) θ = 300°
2) For angles between 0° and 60°, the cosine value is greater than [tex]\frac{1}{2}[/tex].
What is an angle in standard position?
"The position of an angle with its vertex at the origin and its initial side coinciding with the positive x-axis."
For given question,
We have been given an angle θ = 60°
We need to find other value of θ is for which cos(θ) = [tex]\frac{1}{2}[/tex]
We know that, cos(θ) is positive in the first and fourth quadrant.
Also, cos(2π - θ) = cos(θ)
So, cos(60) = cos(360 - 60)
= cos(300)
= [tex]\frac{1}{2}[/tex]
This means, the other value of θ is for which cos(θ) = [tex]\frac{1}{2}[/tex] is , θ = 300°
Also, we know that,
i) cos(0) = 1
ii) cos(30) = [tex]\frac{\sqrt{3} }{2}[/tex]
= 0.866
iii) cos(45) = [tex]\frac{1}{\sqrt{2} }[/tex]
= 0.7071
iv) cos(60) = [tex]\frac{1}{2}[/tex]
= 0.5
This means, for angles between 0° and 60°, the cosine value is greater than [tex]\frac{1}{2}[/tex].
Therefore, 1) θ = 300°
2) For angles between 0° and 60°, the cosine value is greater than [tex]\frac{1}{2}[/tex].
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