A small light bulb is connected to a 20 V battery and draws 1.25 A of current. What is the net resistance of the bulb? *

Respuesta :

The net resistance of the bulb : 16 Ω

Further explanation

Electric current (symbolized by the letter "i) is the amount of charge flowing in the conductor of each unit of time  

Can be formulated:  

[tex]\large{\boxed{\bold{I=\frac{Q}{t}}}[/tex]

Q = charge (Coulomb)  

t = time (seconds)  

The international standard unit of electric current is Coulomb/second or Ampere (A).  

Electric current is also a ratio between the voltage and the amount of resistance at the conductor.  

Can be formulated  

[tex]\large{\boxed{\bold{I=\frac{V}{R}}}[/tex]

V = Voltage (volts)  

R = resistance (ohms)  

This formula is also known as Ohm's Law

A small light bulb is connected to a 20 V battery and draws 1.25 A of current, so,

[tex]\tt V=20~V\\\\I=2.5~A[/tex]

the resistance :

[tex]\tt R=\dfrac{V}{I}\\\\R=\dfrac{20}{1.25}\\\\R=16~ohm[/tex]