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9. The following is for problems #7-12.
In parallelogram ABCD, AD = 19, EC = 15, m ABC = 66', mZDAC = 78
and mZBDC = 19'.
Find mZDAB.

9 The following is for problems 712 In parallelogram ABCD AD 19 EC 15 m ABC 66 mZDAC 78 and mZBDC 19 Find mZDAB class=

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Answer:

m∠DAB is 114°

Step-by-step explanation:

The given parameters are;

The dimensions of the given parallelogram ABCD are AD = 19, EC = 15, m∠ABC = 66°, m∠DAC = 78°, m∠BDC = 19°

Given that in parallelogram ABCD, the same side interior angles are supplementary, we have;

m∠ABC and m∠DAB are supplementary

Therefore;

m∠ABC + m∠DAB = 180° by definition of supplementary angles

66° + m∠DAB = 180°

m∠DAB = 180° - 66° = 114°

m∠DAB = 114°.

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