Answer:
Half-reactions:
Cr³⁺ + 1e⁻ → Cr²⁺; Zn → Zn²⁺ + 2e⁻
Net ionic equation:
2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺
Explanation:
The Cr³⁺ is reduced to Cr²⁺:
Cr³⁺ + 1e⁻ → Cr²⁺ -Half-reaction 1-
Zn is oxidized to Zn²⁺:
Zn → Zn²⁺ + 2e⁻ -Half-reaction 2-
Twice the reduction of Cr:
2Cr³⁺ + 2e⁻ → 2Cr²⁺
Now this reaction + Oxidation of Zn:
2Cr³⁺ + 2e⁻ + Zn → 2Cr²⁺ + Zn²⁺ + 2e⁻
2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺ - Net ionic equation
