Answer:
Maximize 0.039x + 0.033y
Subject to 0 ≤ x ≤ 45
0 ≤ y ≤ 67
x + y ≤ 100
Step-by-step explanation:
From the given information:
To maximize detergent from at most 100 gal of oil.
Assumptions:
Let assume that oil with 3.9% detergent is denoted by x; &
oil with 3.3% detergent is denoted by y
To maximize:
0.039x + 0.033y
As x can only supply at most 45 gal;
Then, 0 ≤ x ≤ 45 (since no negative supply is possible)
And, y can only supply at most 67 gal;
Then, 0 ≤ y ≤ 67 (since no negative supply is possible)
Now, if we take at most 100 gal, we have;
x + y ≤ 100
Therefore, the final solution is:
Maximize 0.039x + 0.033y
Subject to 0 ≤ x ≤ 45
0 ≤ y ≤ 67
x + y ≤ 100
