You can consult the previous question of yours that I answered [19947994] for the first part of this one. Just swap out the starting height, velocity, and launch angle. You would get an airtime of about t ≈ 5.097 s.
For this problem, the rock travels a horizontal distance x after time t according to
x = (19 m/s) cos(63°) t
Plug in the airtime:
x = (19 m/s) cos(63°) (5.097 s) ≈ 43.96 m ≈ 44 m
