Respuesta :
This problem is relatively simple, in order to solve this problem the only formula you need to know is the formula for friction, which is:
Ff = UsN
where Us is the coefficient of static friction and N is the normal force.
In order to get the crate moving you must first apply enough force to overcome the static friction:
Fapplied = Ff
Since Fapplied = 43 Newtons:
Fapplied = Ff = 43 = UsN
and it was given that Us = 0.11, so all you have to do is isolate N by dividing both sides by 0.11
43/0.11 = N = 390.9 which is approximately 391 or C. 3.9x10^2
Ff = UsN
where Us is the coefficient of static friction and N is the normal force.
In order to get the crate moving you must first apply enough force to overcome the static friction:
Fapplied = Ff
Since Fapplied = 43 Newtons:
Fapplied = Ff = 43 = UsN
and it was given that Us = 0.11, so all you have to do is isolate N by dividing both sides by 0.11
43/0.11 = N = 390.9 which is approximately 391 or C. 3.9x10^2
The value of the normal force will be 390.909 N.
What is the coefficient of static friction?
The ratio of the greatest static friction force (F) between the surfaces in contact before movement begins to the normal (N) force is the coefficient of static friction.
The given data in the problem is;
Force on the crate by Marry, F₁= 18 newtons.
Force on the crate by Marry and Anne, F₂ = 43 newtons.
Coefficient of static friction,[tex]\rm \mu_s = 0.11[/tex]
The normal force is, R =?
As the object starts moving, the friction force is equal to the applied force on the crate by Marry and Anne.
f = F₂
The friction force,f offered by the crate is;
[tex]\rm f = \mu_s R[/tex]
43 N = 0.11 × R
R = 390.909 N
Hence, the value of the normal force will be 390.909 N.
To learn more about the coefficient of static friction, refer to
https://brainly.com/question/17237604
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