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A bag contains 4 red marbles and 6 blue marbles. Brandon selects one marble from the bag. Without replacing the marble he then selects a second marble. What is the probability that he first selects a blue marble and then selects a red marble?

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texaschic101
4 red marbles and 6 blue marbles...total of 10 marbles

probability of first marble being blue = 6/10
without replacing
probability of second marble being red = 4/9

probability of both events happening = 6/10 * 4/9 = 24/90 reduces to 4/15

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