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Two trains are 348 miles apart, and their speeds differ by 22 mph. Find the speed of each train if they are traveling toward each other and will meet in 3 hours

Respuesta :

SJ2006

Total distance between the trains = 348 miles

Total time to cross that distance by trains =  3 h.

So, sum of their speed would be: 348/3 = 116

A.T.Q,

Speed of train 1 - speed of train 2 = 22

so, two equation that has formed are:

a+b=116

a-b=22, a=b+22

Substitute that in above equation; b+22+b=116

2b= 94, b=47 & a=116-47 =69

Speed of the TRAIN IS 47 & 69 miles per hour.

Did you understand?



olemakpadu
The two trains are 348 miles apart:

Since the speed of both trains differ by 22 mph

Let the speeds be x and x + 22

Distance = Speed * time

In 3 hours the train traveling x mph would have traveled = 3*x = 3x miles.

In 3 hours the train traveling (x+22) mph would have traveled = 3*(x+22)

= 3*x + 3*22 = 3x + 66 miles.  

Total = 3x + 3x + 66 = 348

3x + 3x + 66 = 348

6x + 66 = 348

6x = 348 - 66

6x = 282

x = 282/6

x = 47

Recall the speeds of each train were x, and (x + 22) mph

x = 47,   x + 22 = 47 + 22 = 69

So speed of each train is 47 mph and 69 mph

I hope this helped. 
 

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