Explanation:
It is given that mass of chlorine is 325 g and molar mass of [tex]CaCl_{2}[/tex] is 110.98 g/mol.
Hence, calculate the number of moles as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{325 g}{110.98 g/mol}[/tex]
= 2.92 mol
As there are two chlorine atoms present in [tex]CaCl_{2}[/tex]. Hence, number of moles present in 2 chlorine atoms will be as follows.
[tex]2 \times 2.92[/tex]
= 5.85 mol
Therefore, mass of chlorine present in 5.85 mol of [tex]CaCl_{2}[/tex] will be as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
5.85 mol = [tex]\frac{mass}{110.98 g/mol}[/tex]
mass = 649.23 g
Therefore, we can conclude that 649.23 g of Cl are present in given [tex]CaCl_{2}[/tex] compound.
