Answer:
S = 415.64m
Explanation:
Given the following data;
Time, t = 9.21secs
Since it's a free fall, acceleration due to gravity = 9.8m/s²
Initial velocity, u = 0
To find the height of the tower, we would use the second equation of motion;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Where;
- S represents the displacement or height measured in meters.
- u represents the initial velocity measured in meters per seconds.
- t represents the time measured in seconds.
- a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
[tex] S = 0*9.21 + \frac {1}{2}*(9.8)*9.21^{2}[/tex]
[tex] S = 0 + 4.9*84.8241[/tex]
[tex] S = 4.9*84.8241 [/tex]
Height, S = 415.64m
Therefore, the tower is 415.64m in height.
