Answer: y=-2x-9
Step-by-step explanation:
If ANGL is a square, then NG and LG are adjacent sides.
Adjacent sides are perpendicular. [Each angle is 90°]
The equation of line NG is [tex]Y=\dfrac12 X-6[/tex].
By comparing it to equation in slope intercept form y=mx+c ( where , m= slope , c=y-interecpt)
slope =[tex]\dfrac12[/tex]
Let slope of LG be n, then
[tex]n\times \dfrac{1}{2}=-1[/tex] [Product of slopes of two perpendicular line =-1]
[tex]\Rightarrow n=-2[/tex]
Equation of a line passes through (a,b) and have slope m is given by :-
[tex](y-b)=m(x-a)[/tex]
Equation of LG :
[tex](y-1)=-2(x-(-5))\\\\\Rightarrow\ y-1=-2x-10\\\\\Rightarrow\ y=-2x-9[/tex] [In intercept form]
