The partial pressure of Gas B : 1.3 atm
Dalton's Law stated
the total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases
Can be formulated:
[tex]\tt P~tot=P1+P2+P3...Pn[/tex]
P tot = 2 atm
P gas A = 0.7 atm
So P gas B :
[tex]\tt P~gas~B=P~tot-P~gas~A\\\\P~gas~B=2-0.7=1.3~atm[/tex]
The partial pressure of Gas B in the mixture of two gases has been 1.3 atm.
The partial pressure of the gas can be defined as the pressure of the particular gas in the mixture of gases.
According to dalton, the total pressure of the gas has been the sum of the partial pressure of the individual gases.
Thus, total pressure = partial pressure of gas A + partial pressure of gas B
Given, total pressure = 2 atm
The partial pressure of gas A = 0.70 atm
So, the partial pressure of Gas B = total pressure - partial pressure of gas A
The partial pressure of Gas B = 2.0 atm - 0.70 atm
The partial pressure of Gas B = 1.3 atm
Thus, the partial pressure of Gas B in the mixture of two gases has been 1.3 atm.
For more information about the partial pressure, refer to the link:
https://brainly.com/question/8408970
