Answer:
The equation is y =6x-84.
Step-by-step explanation:
We need to find the equation of the line that is perpendicular to the given line and passes through the given point.
y = − 1/6x − 5; (14, 0)
Slope of required line
The equation of given line [tex]y = - \frac{1}{6} x - 5[/tex] is in slope-intercept form.
Comparing it with general formula of slope-intercept form [tex]y=mx+b[/tex] where m is slope and b is y-intercept. The slope of line m is: -1/6
So, the slope of required line that is perpendicular to given line is 6 because the equation of line that we need to find is perpendicular to the given line, so their slopes will be: [tex]m_1=-\frac{1}{m_2}[/tex]
So, slope = 6
Finding y-intercept of required line
Using slope =6 and point (14,0) we can find y-intercept of required line by slope-intercept formula
[tex]y=mx+b\\0=6(14)+b\\0=84+b\\b=-84[/tex]
Equation of required line:
The equation of required line having slope (m)= 6 and y-intercept (b)= -84 is:
[tex]y=mx+b\\y=6x-84[/tex]
The equation is y =6x-84.
