Answer:
Perimeter of Triangle ABC is 21
Step-by-step explanation:
According to the Midpoint Theorem, if the line segment adjoins midpoints of any of the sides of a triangle, then the line segment is said to be parallel to all the remaining sides, and it measures about half of the remaining sides.
In this case, since XY=7, then AZ+ZC will need to equal 14 as that's opposite of half. Since AZ=ZC given that they are congruent, then AZ=7. Therefore the perimeter is XA+XZ+AZ=5+9+7=21
