Respuesta :
Answer:
Explanation:
Na₂CO₃ (aq)+ MgCl₂ (aq) = MgCO₃(s) +2NaCl (aq)
MgCO₃(s) is the precipitate .
Ionic equation
2 Na⁺¹ + CO₃⁻² + Mg⁺² + 2 Cl⁻¹ = MgCO₃(s) +2 Na⁺ + 2 Cl⁻
net ionic equation
Mg⁺² + CO₃⁻² = MgCO₃ (s) .
The precipitate formed in the reaction has been the magnesium carbonate salt. The net ionic equation will be: [tex]\rm Mg^2^+\;+\;CO_3^2^-\;\rightarrow\;MgCO_3[/tex].
The mixture of sodium carbonate and magnesium chlorate has been given as:
[tex]\rm Na_2CO_3\;+\;MgCl_2\;\rightarrow\;MgCO_3\;+\;NaCl[/tex]
- The precipitate formed in the reaction has been the magnesium carbonate salt.
- The chemical equation has been written as the equation with the states of the reactants and the products.
[tex]\rm Na_2CO_3\;(aq)\;+\;MgCl_2\;(aq)\;\rightarrow\;MgCO_3\;(s)\;+\;2\;NaCl\;(aq)[/tex]
- The ionic equation for the reaction has been:
[tex]\rm Na_2CO_3\;\rightarrow\;2\;Na^+\;+\;CO_3^2^-[/tex]
[tex]\rm MgCl_2\;\rightarrow\;Mg^2^+\;+\;2\;Cl^-[/tex]
[tex]\rm MgCO_3\;\rightarrow\;Mg^2^+\;+\;CO_3^2^-[/tex]
[tex]\rm NaCl\;\rightarrow\;Na^+\;+\;Cl^-[/tex]
The ionic equation for the reaction will be:
[tex]\rm 2\;Na^+\;+\;CO_3^2^-\;+\;Mg^2^+\;+\;2\;Cl^-\;\rightarrow\;MgCO_3\;+\;2\;Na^+\;+\;2\;Cl^-[/tex]
- The net ionic equation has been consisted of the products that have been different on both the product and the reactant side. The same ions are eliminated in the net ionic equation. The net ionic equation will be:
[tex]\rm Mg^2^+\;+\;CO_3^2^-\;\rightarrow\;MgCO_3[/tex]
For more information about the net ionic equation, refer to the link:
https://brainly.com/question/22885959
