Answer:
45 ways
Step-by-step explanation:
Combination method is appropriate for this question since it deals with arrangement.
i.e [tex]^{n}C_{r}[/tex] = [tex]\frac{n!}{(n - r)!r!}[/tex]
Since 8 records are to be selected from 10 available records. Then, the number of ways for the arrangement of the records can be determined as;
Let n = 10 and r = 8
[tex]^{10}C_{8} }[/tex] = [tex]\frac{10!}{(10 - 8)!8!}[/tex]
= [tex]\frac{10!}{2!8!}[/tex]
= [tex]\frac{10*9*8*7*6*5*4*3*2!}{2!8*7*6*5*4*3*2!}[/tex]
= [tex]\frac{10*9}{2}[/tex]
= 45
Therefore, the number of ways by which the records can be arranged is 45.