A dog chases a skateboarder travelling at 10.4m/s.The skateboarder speeds up with a constant acceleration for 39m over 3.3s. We want to find the acceleration of the skateboarder over the 3.3s time interval.

Respuesta :

Answer:

The acceleration of the skateboarder over the 3.3s time interval is 3.15 m/s²

Explanation:

Acceleration can be described as the rate of change of velocity (as seen in the question). The formula to be used here to determine the acceleration is

Acceleration (in m/s²) = velocity (m/s) ÷ time (s)

Acceleration = 10.4 ÷ 3.3

Acceleration = 3.15 m/s²

Thus, the acceleration of the skateboarder over the 3.3s time interval is 3.15 m/s²