Write an informal proof to show triangles ABC and DEF are similar. Please don’t answer if you don’t know!!
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Answer:
ΔABC ~ ΔDEF
Step-by-step explanation:
If the given triangles ΔABC and ΔDEF are similar,
Their corresponding sides will be proportional.
[tex]\frac{\text{AB}}{\text{DE}}=\frac{\text{BC}}{\text{EF}}=\frac{\text{AC}}{\text{DF}}[/tex]
By substituting the measures of the given sides,
[tex]\frac{4}{2}=\frac{6}{3}=\frac{2}{1}[/tex]
2 = 2 = 2
Since, corresponding sides of both the triangles are proportional, both the triangles will be similar.
ΔABC ~ ΔDEF