Answer:
The acceleration of man 1 and 2 is [tex]3.125\ m/s^2[/tex] and [tex]4.167\ m/s^2[/tex].
Explanation:
Mass of man 1, m₁ = 80 kg
Mass of man 2, m₂ = 60 kg
One man pulls on the rope with a force of 250 N.
Let a₁ is acceleration of man 1,
F = m₁a₁
[tex]a_1=\dfrac{F}{m_1}\\\\a_1=\dfrac{250}{80}\\\\a_1=3.125\ m/s^2[/tex]
Let a₂ is acceleration of man 1,
F = m₂a₂
[tex]a_2=\dfrac{F}{m_2}\\\\a_2=\dfrac{250}{60}\\\\a_2=4.167\ m/s^2[/tex]
So, the acceleration of man 1 and 2 is [tex]3.125\ m/s^2[/tex] and [tex]4.167\ m/s^2[/tex].
