Respuesta :

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[tex]y = 16 {x}^{2} + 1[/tex]

Subtract sides 1

[tex]y - 1 = 16 {x}^{2} + 1 - 1[/tex]

[tex]y - 1 = 16 {x}^{2} [/tex]

[tex]16 {x}^{2} = y - 1[/tex]

Divide sides by 16

[tex] \frac{16 {x}^{2} }{16} = \frac{y - 1}{16} \\ [/tex]

[tex] {x}^{2} = \frac{y - 1}{16} \\ [/tex]

[tex]x = ± \sqrt{ \frac{y - 1}{16} } \\ [/tex]

[tex]x = ± \: \frac{1}{4} \sqrt{y - 1} \\ [/tex]

Thus ;

[tex] {f}^{ - 1} (x) = ± \: \frac{1}{4} \sqrt{y - 1} \\ [/tex]

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