Answer:
[tex]\underline{ \boxed{\frac{37}{5} < x < 9 }}[/tex]
Step-by-step explanation:
[tex] \underline{ \boxed{my \: dear....you \: will \: need \: to \: apply \: many \: logical \: approach...}} \\ \underline{ \boxed{...and \: geometric \: rules}} \to \\ applying \: sine \: rule \to \\ \sin((7x + 4)) = \frac{opp}{adj} = \frac{12}{14} \\ (7x + 4) = \sin {}^{ - 1} (0.8571428571) \\ 7x + 4 = 58.99 7\\ 7x = 58.997 - 4 \\ 7x = 54.997\\ x = \frac{54.997}{7} \\ \underline{ \boxed{x = 7.8 = \frac{39}{5} }} \\ therefore \: the \: required \: inequality \: is \to \\ \underline{ \boxed{\frac{37}{5} < x < 9 }} \: \\ ......... \: ....... [/tex]
♨Rage♨
