The specific heat capacity will be 400 J/kg °C. Specific heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.
The amount of heat required to increase a substance's temperature by one degree Celsius is known as specific heat capacity.
Similarly
Mathematically, specific heat capacity is given by;
[tex]\rm C = \frac{E}{m \times \theta }[/tex]
The given data in the problem is;
The specific heat of the substance is,C in J/kg °C.
The energy is,E =1000 JIs
The mass is,m= 25 g
[tex]\rm \theta[/tex] Is the temperature difference = 100 °C.
On substituting the given data;
[tex]\rm C = \frac{E }{m \times \theta } \\\\ C = \frac{1000}{25\times 10^{-3} \times 100 } \\\\ C = 400 \ J/kg^0C.[/tex]
Hence, the specific heat capacity will be 400 J/kg °C.
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