Answer:
[tex]\rho= 6.51g/cm^3[/tex]
Explanation:
Hello!
In this case, since the density is defined as the degree of compactness of a substance, and is defined as the mass over the volume:
[tex]\rho= \frac{m}{V}[/tex]
Given the displaced volume, we can compute the volume of the piece of metal via the following subtraction:
[tex]V=67.50mL-50.00mL=17.50mL=17.50cm^3[/tex]
Since the piece of metal displaces the water to the final volume. Moreover, given the mass in lb, we compute it grams as follows:
[tex]m=0.251lb*\frac{453.6g}{1lb} =113.85g[/tex]
Thus, the density turns out:
[tex]\rho= \frac{113.85g}{17.50cm3}\\\\\rho= 6.51g/cm^3[/tex]
Best regards.
