Answer:
[tex]V_{H_2O}=460 mL[/tex]
Explanation:
Hello!
In this case, in a dilution process, water is added to a solute in order to decrease its concentration but increase the volume of the solution. It means that if we have 20.0 mL of a 12.0-M solution of HCl and we want a 0.500-M solution, we need to apply the following formula considering that the moles remain unchanged:
[tex]M_1V_1=M_2V_2[/tex]
Thus, solving for the final volume is:
[tex]V_2=\frac{M_1V_1}{M_2}[/tex]
So plugging in the values we obtain:
[tex]V_2=\frac{12.0M*20.0mL}{0.500M}\\\\V_2=480 mL[/tex]
Now, since the initial volume of acid was 20.0 mL and the final volume is 480 mL, the added volume of distilled water is:
[tex]V_{H_2O}=480-20=460 mL[/tex]
Best regards!
