Answer:
[tex]Cv_{calorimeter}=18.4kcal/K[/tex]
Explanation:
Hello!
In this case, since the combustion of the hamburger released 335.4 kcal of energy and that energy is received by the calorimeter, we can write:
[tex]Q_{hamburguer}=-Q_{calorimeter}[/tex]
And the heat of the calorimeter is written in terms of the temperature change and the calorimeter constant:
[tex]Q_{hamburguer}=-Cv_{calorimeter}\Delta T[/tex]
Thus, given the released heat by the hamburger due to its combustion and the temperature change, Cv for the calorimeter turns out:
[tex]Cv_{calorimeter}=\frac{-Q_{hamburguer}}{\Delta T} =\frac{-(-335.4kcal)}{18.2K}\\\\Cv_{calorimeter}=18.4kcal/K[/tex]
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