Answer:
[tex](10.3(2.5)+3.1(2))\div 110[/tex]
Step-by-step explanation:
[tex]A_1[/tex] = Area of 1st rectangle = [tex](10.3\times 2.5)\ \text{ft}^2[/tex]
[tex]A_2[/tex] = Area of 2nd rectangle = [tex](3.1\times 2)\ \text{ft}^2[/tex]
[tex]1\ \text{pound of grout}=110\ \text{ft}^2[/tex]
[tex]\Rightarrow 1\ \text{ft}^2=\dfrac{1}{110}\ \text{pound of grout}[/tex]
The number of pounds required for the counter top is
[tex]\text{Total area}\times \text{The amount of grout used in 1 ft}^2[/tex]
[tex]=A_1+A_2\times \dfrac{1}{110}=(10.3(2.5)+3.1(2))\times \dfrac{1}{110}\\ =(10.3(2.5)+3.1(2))\div 110[/tex]
The required expression is [tex](10.3(2.5)+3.1(2))\div 110[/tex].
