CH3CH2OH + 302 → 2002 + 3H20
What would be the limiting reactant in the reaction if 1 mole of
oxygen gas and 1 mole of ethanol (CH3CH2OH) reacted with
each other?

Respuesta :

Answer:

Oxygen gas

Explanation:

 Given expression:

          CH₃CH₂OH + 3O₂ → 2CO₂ + 3H₂O

Number of moles of oxygen gas  = 1 mole

Number of moles of ethanol = 1 mole

Unknown:

The limiting reactant  = ?

Solution:

The limiting reactant is the reactant in short supply in a chemical reaction. To find this specie, we always us the number of moles.

  From the equation of the reaction:

        1 mole of ethanol would require 3 moles of oxygen gas

 But we have been given just 1 mole of oxygen gas instead of 3moles.

 Therefore, oxygen gas is the limiting reactant.

 

The limiting reactant for the reaction involving 1 mole of oxygen gas and 1 mole of ethanol is oxygen gas, O₂

Balanced equation

CH₃CH₂OH + 3O₂ —> 2CO₂ + 3H₂O

From the balanced equation above,

3 moles O₂ reacted with 1 mole of CH₃CH₂OH

How to determine the limiting reactant

From the balanced equation above,

3 moles O₂ reacted with 1 mole of CH₃CH₂OH.

Therefore,

1 mole of O₂ will react with = 1 / 3 = 0.33 mole of CH₃CH₂OH

From the calculation made above, we can see that only 0.33 mole out of 1 mole of CH₃CH₂OH given, is needed to react completely with 1 mole of O₂.

Therefore, O₂ is the limiting reactant.

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